Calculus - Differentiation - Applications of Calculus.
Given an equation - Test Yourself 2.
The questions of this page focus on the following issues: |
1. Finding stationary points. |
2. Where is a curve increasing/decreasing. |
3. The concavity of the curve. |
4. The points of inflexion. |
5. The number of solutions for an equation. |
Stationary points and sketching. | 1. A function is defined as f(x) = x3 - 3x2.
Answer. (i) Maximum at (0,0); |
2. For the cubic function y = x3 - x2 - x + 6
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3. The function f(x) = 2x3 + 3x2 - 12x + 7 is defined with the domain [-3. 3].
Answer. (i) Maximum at (-2,27); minimum at (-1, 0). (ii) POI at (-0.5, 13.5). (iv) Max value in domain is 52. (v) -0.5 < x < 1. |
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4. The function f(x) = x3 - 6x2 + 9x -4 is defined in the domain [0, 4].
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. | 5. Given that f(x) = (x - 2)2(3 - x):
Answer. (ii) Maximum at (8/3,4/27); minimum at (2, 0). (iIi) Intercepts at (2, 0) and at (0, 12). |
Absolute maximum & minimum values | |
Curve increasing/decreasing. | 6. (i) For the curve y = 3x - x3, find the stationary points and determine their nature.
Answer. (i) Maximum at (1,2); |
Concavity | 7. A function is defined by f(x) = x3 - 3x2 - 9x - 22.
Answer. (i) TPs at (-1, 27) max and (3, -5) min; (ii) POI at (1, 11). (iv) x > 1. |
8. For what values of x is the curve f(x) = 2x3 + x2 concave down?
Answer. Concave down for x < 1/6. |
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Points of inflexion. | 9. The diagram below shows a sketch of the curve y = 6x2 - x3.
The curve cuts the x-axis at C. It also has point of inflexion at A and a local maximum at B.
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10. | |
Number of solutions. | 11. |
12. |